I'm not sure what you mean. To give ONE example: Earlier I could use this code on top of every page: if ($printout != "yeah") { include("header.php"); } This code gives an error today. The variable $printout is set if the visitor choose to click on the 'print_page_image', otherwise the variable has no value.
"Esteban FernáNdez" <[EMAIL PROTECTED]> skrev i meddelandet news:[EMAIL PROTECTED] > When you recivied that error ?, in a form ?, if is in a Form just put in the > top of .php files this code > > $HTTP_GET_VARS["variable2"]; > $HTTP_GET_VARS["variable3"]; > > Of course if you send with other method (post) change the GET for POST > > $HTTP_POS_VARS["variable2"]; > $HTTP_POS_VARS["variable3"]; > > Regards. > > Esteban. > > > > "ØYstein HåLand" <[EMAIL PROTECTED]> escribió en el mensaje > news:[EMAIL PROTECTED] > > None of my old scripts worx nowadays and the most common error message is > > 'undefined variable'. What is the best/simplest way to work around this > > situation? > > if !isset($myvar) { > > do this > > blah blah > > } > > ? > > > > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php