sorry, forgot to attach the test cases.Postgres 13 | db<>fiddle
| | | | Postgres 13 | db<>fiddle Free online SQL environment for experimenting and sharing. | | | On Friday, May 21, 2021, 03:59:18 PM PDT, Nagaraj Raj <nagaraj...@yahoo.com> wrote: Hi, This is also not working, create table mytable_z partition of mytable for values from ('Z') to ('[')partition by range(id); ERROR: empty range bound specified for partition "mytable_z"DETAIL: Specified lower bound ('Z') is greater than or equal to upper bound ('[').SQL state: 42P17 DB running on version PostgreSQL 11.6, compiled by Visual C++ build 1800, 64-bit On Friday, May 21, 2021, 02:00:38 PM PDT, Michel SALAIS <msal...@msym.fr> wrote: #yiv1392522220 -- filtered {}#yiv1392522220 filtered {}#yiv1392522220 filtered {}#yiv1392522220 filtered {}#yiv1392522220 filtered {}#yiv1392522220 p.yiv1392522220MsoNormal, #yiv1392522220 li.yiv1392522220MsoNormal, #yiv1392522220 div.yiv1392522220MsoNormal {margin:0cm;font-size:11.0pt;font-family:sans-serif;}#yiv1392522220 a:link, #yiv1392522220 span.yiv1392522220MsoHyperlink {color:blue;text-decoration:underline;}#yiv1392522220 span.yiv1392522220EmailStyle20 {font-family:sans-serif;color:windowtext;}#yiv1392522220 .yiv1392522220MsoChpDefault {font-size:10.0pt;}#yiv1392522220 filtered {}#yiv1392522220 div.yiv1392522220WordSection1 {}#yiv1392522220 Hi I don’t discuss here the choice itself but this is not correct: create table mytable_z of mytable for values from ('Z') to ('Z['); It should be create table mytable_z of mytable for values from ('Z') to ('[') Michel SALAIS De : Nagaraj Raj <nagaraj...@yahoo.com> Envoyé : vendredi 21 mai 2021 18:39 À : David Rowley <dgrowle...@gmail.com> Cc : Justin Pryzby <pry...@telsasoft.com>; Pgsql-performance <pgsql-performa...@postgresql.org> Objet : Re: Partition with check constraint with "like" Hi David, Hi, I am trying to create partitions on the table which have around 2BIL records and users will always look for the "name", its not possible to create a partition with a list, so we are trying to create a partition-based first letter of the name column. name column has a combination of alpha numeric values. > postgres=# select chr(ascii('z')+1) ; > chr > ----- > { > (1 row) I tried as below, I'm able to create a partition table for 'Z', but it's not identifying partition table. postgres=# select chr(ascii('Z')+1) ; chr ----- [ (1 row) create table mytable_z of mytable for values from ('Z') to ('Z['); CREATE TABLE insert into mytable values(4,'ZAR83NB'); ERROR: no partition of relation "mytable" found for row DETAIL: Partition key of the failing row contains (name) = (ZAR83NB). SQL state: 23514 On Friday, May 21, 2021, 01:24:13 AM PDT, David Rowley <dgrowle...@gmail.com> wrote: On Fri, 21 May 2021 at 19:02, Nagaraj Raj <nagaraj...@yahoo.com> wrote: > then what would be the range of Z > FROM (Z) to (?) ; postgres=# select chr(ascii('z')+1) ; chr ----- { (1 row) > same way for 9 postgres=# select chr(ascii('9')+1) ; chr ----- : (1 row) https://en.wikipedia.org/wiki/ASCII You can also use MINVALUE and MAXVALUE to mean unbounded at either end of the range. But is there a particular need that you want to partition this way? It seems like it might be a bit painful to maintain, especially if you're not limiting yourself to ASCII or ANSI characters. You might want to consider HASH partitioning if you're just looking for a way to keep your tables and indexes to a more manageable size. You've not really mentioned your use case here, so it's hard to give any advice. There are more details about partitioning in https://www.postgresql.org/docs/current/ddl-partitioning.html David