On Wed, Jul 30, 2014 at 4:06 PM, Fabien COELHO <coe...@cri.ensmp.fr> wrote:
> > double dx = 0.0, dy = 0.0; >> >> if (point->x < box->low.x) >> dx = box->low.x - point->x; >> if (point->x > box->high.x) >> dx = point->x - box->high.x; >> if (point->y < box->low.y) >> dy = box->low.y - point->y; >> if (point->y > box->high.y) >> dy = point->y - box->high.y; >> return HYPOT(dx, dy); >> >> I feel myself quite tangled. >> Could anybody clarify it for me? Did I miss something? Thanks. >> > > ISTM that you miss the projection on the segment if dx=0 or dy=0. I don't need to find projection itself, I need only distance. When dx = 0 then nearest point is on horizontal line of box, so distance to it is dy. Same when dy = 0. When both of them are 0 then point is in the box. ------ With best regards, Alexander Korotkov.
