I've never had that happen before, and I've used Perl and DBI a lot.

Susan


On Wed, Apr 16, 2014 at 5:34 PM, Robert DiFalco <robert.difa...@gmail.com>wrote:

> Two common cases I can think of:
>
> 1. The PERL framework is only caching the insert and does not actually
> perform it until commit is issued.
> 2. You really are not on the same transaction even though it appears you
> are and the transaction isolation is such that you cannot see the insert
> until it is fully committed.
>
>
> On Wed, Apr 16, 2014 at 5:28 PM, David G Johnston <
> david.g.johns...@gmail.com> wrote:
>
>> One possibility is that the INSERT is going to a different table (having
>> the
>> same name but existing in a different schema) that is visible/default to
>> the
>> function but not outside of it.
>>
>> Or the function on the server is not "current" and thus isn't doing what
>> you
>> think it is.
>>
>>
>> > I do an insert via a function, which returns the new id, then later I
>> try
>> > to SELECT on that id, and it doesn't find it.
>> >
>> > Could it be because the insert is done inside a function?
>>
>> Not by itself; but that factor could be interacting with something else to
>> cause the observed behavior.  As noted above functions are able to
>> maintain
>> their own "schema" environment so what is executed in one and outside of
>> one
>> can indeed target different physical objects - which has nothing to do
>> with
>> transaction visibility.
>>
>>
>> Susan Cassidy-3 wrote
>> > It is a fairly large and complex Perl program, so no, not really.
>>
>> Then you need to recreate a functionally similar, but limited, test case
>> that either exhibits the behavior in question or causes you to realize
>> what
>> you are doing in wrong in the "large and complex Perl program".
>>
>> David J.
>>
>>
>>
>>
>> --
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>>
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