On Thu, 17 May 2007 11:13:45 -0700 "jerry gay" <[EMAIL PROTECTED]> wrote: > char *s = s_key; > *s = 0;
> however... why is 's' nulled out, directly after it's initialized to > 's_key'? that looks funny. The first line declares a pointer, pointing to s_key. The second line sets the first byte of s_key's buffer to 0 (the pointer value itself doesn't change). Mark