On Wed, Jun 01, 2005 at 08:45:53PM +0200, Leopold Toetsch wrote:
> Nick Glencross wrote:
>
> >Doh! Copied the wrong 'perl -V' output!
> >
> > intsize=4, longsize=4, ptrsize=4, doublesize=8, byteorder=4321
> > d_longlong=define, longlongsize=8, d_longdbl=define, longdblsize=16
> > ivtype='long', ivsize=4, nvtype='double', nvsize=8, Off_t='off_t',
> >lseeksize=4
> > alignbytes=8, prototype=define
> ^^^^^^^^^^^^
>
> What does this mean in perl?
It's the result from this C program run by Configure:
#include <stdio.h>
struct foobar {
char foo;
NV bar;
} try_algn;
int main()
{
printf("%d\n", (int)((char *)&try_algn.bar - (char *)&try_algn.foo));
return(0);
}
"alignbytes" isn't the most helpful name. NV is usually a double.
Nicholas Clark
