See my 2 comments:
> new P0, .PerlInt
> new P1, .PerlInt
> new P2, .PerlInt
> new P3, .PerlInt
> set P0, 10
> set P1, 11
> set P2, 12
>
> # outer most lexical scope
> open_lex
^^^^^^^^ New pad
> store_lex P0, "a"
> find_lex P3, "a"
> print P3 # prints 10
> print "\n"
>
> # nested lexical scope
> open_lex
> store_lex P1, "b"
> find_lex P3, "b"
> print P3 # prints 11
> print "\n"
>
> store_lex P2, "a" # overwrites previous "a"
^^^^^^^^^^^^^^^^^ Should not "overwrite", should shadow since it is
stored
in the current pad
> find_lex P3, "a"
> print P3 # prints 12
> print "\n"
>
> close_lex # end of nested lexical scope
^^^^^^^^^ Pad goes away, with "b" and "a", so the outer values
should be back in effect.
>
> find_lex P3, "a"
> print P3 # prints 12
> print "\n"
> end
I'll apply this, since it is clean, but the semantics need adjustment.
Thanks,
-Melvin Smith
IBM :: Atlanta Innovation Center
[EMAIL PROTECTED] :: 770-835-6984
