> On Mon, May 06, 2019 at 07:12:39PM -0700, Tony Ewell via perl6-users
wrote:
>> Hi All,
>>
>> What am I doing wrong here?
>>
>> $ p6 'my $x="\$1.23"; $x~~s/("\$") (.*?)/$1USD/; say $x;'
>> USD1.23
>>
>> I am expecting to see `1.23USD`
>>
>> Many thanks,
>> -T
On 5/7/19 3:05 PM, Patrick R. Michaud wrote:
The (.*?) pattern will match an empty string.
Thus $0 gets the dollar sign, $1 is "", and "$" ~ "" (i.e., "$") gets replaced by "" ~
"USD" (i.e., "USD").
So the net result is to replace the single dollar sign by "USD", resulting in
"USD1.23".
You might want to remove the ? modifier from .*?, so that the expresssion is
greedy instead of eager.
Pm
I wasn't "greedy" enough. Chuckle!
Thank you!
