Re: buf to integer?

[ToddAndMargo via perl6-users]

On 2/8/19 9:54 AM, Brad Gilbert wrote:

If you have a new enough version of Rakudo:

     my Buf $x=Buf.new(0xAE,0x5D,0x5C,0x72);

     my int32 $i = $x.read-int32(0,LittleEndian);

     say $i.base(16);
     # 725C5DAE

Thank you!