Ooooooo. Nice. On Fri, 8 Feb 2019, 17:55 Brad Gilbert <b2gi...@gmail.com wrote:
> If you have a new enough version of Rakudo: > > my Buf $x=Buf.new(0xAE,0x5D,0x5C,0x72); > > my int32 $i = $x.read-int32(0,LittleEndian); > > say $i.base(16); > # 725C5DAE > > On Fri, Feb 8, 2019 at 12:35 AM Todd Chester via perl6-users > <perl6-us...@perl.org> wrote: > > > > Hi All, > > > > I am dealing with a Buf what includes 32 bit integers, but > > they are entered somewhat backwards as view with hexedit: > > > > AE 5D 5C 72 represents the number 725C5DAE > > > > This is what I have come up with to convert this type of > > number in a buffer to and integer > > > > $ p6 'my Buf $x=Buf.new(0xAE,0x5D,0x5C,0x72); my int32 $i=$x[3] +< 0x18 > > + $x[2] +< 0x10 + $x[1] +< 0x08 + $x[0]; say $x; say > $i.base(0x10);' > > > > Buf:0x<ae 5d 5c 72> > > 725C5DAE > > > > > > Is there a more "elegant" way to do this? > > > > Many thanks, > > -T >
