> On 14/08/18 12:01, ToddAndMargo wrote: >> Hi All, >> >> >> I presume this is failing as the current directory is not >> in the "lib" path: >> >> >> $ perl6 -MPrintColors 'PrintBlue( "Blue\n" );' >> Could not open PrintBlue( "Blue" ). Failed to stat file: no such >> file or directory >> >> >> This does work, but what a lot of extra work: >> >> $ perl6 -e 'use lib "/home/linuxutil"; use PrintColors; PrintBlue( >> "Blue\n" );' >> Blue >> >> >> >> What are the rules for calling modules from the command line? >> >> >> Many thanks, >> -T
On 08/14/2018 03:16 AM, Timo Paulssen wrote:
You can just put -I lib on your commandline, but what's more important is that you forgot to pass -e, so it was taking your code and interpreting it as a filename. It's very unlikely that you have a file called 'PrintBlue( "Blue\n" );' in the current directory, though. perl6 -Ilib -MPrintColors -e 'PrintBlue( "Blue\n");' should do what you meant to do. HTH - Timo
Hi Timo, It took me a minute to figure out that the "lib" in "Ilib" was not part of the command. I even searched the perl6 docs for Ilib. $ perl6 -I./ -MPrintColors -e 'PrintBlue( "Blue\n" );' Blue Thank you! -T This time I am writing this down!
