You can just put -I lib on your commandline, but what's more important is that you forgot to pass -e, so it was taking your code and interpreting it as a filename. It's very unlikely that you have a file called 'PrintBlue( "Blue\n" );' in the current directory, though.
perl6 -Ilib -MPrintColors -e 'PrintBlue( "Blue\n");' should do what you meant to do. HTH - Timo On 14/08/18 12:01, ToddAndMargo wrote: > Hi All, > > > I presume this is failing as the current directory is not > in the "lib" path: > > > $ perl6 -MPrintColors 'PrintBlue( "Blue\n" );' > Could not open PrintBlue( "Blue" ). Failed to stat file: no such > file or directory > > > This does work, but what a lot of extra work: > > $ perl6 -e 'use lib "/home/linuxutil"; use PrintColors; PrintBlue( > "Blue\n" );' > Blue > > > > What are the rules for calling modules from the command line? > > > Many thanks, > -T
