Re: Why use dd to convert a string to an integer?

[ToddAndMargo]

On Tue, 7 Aug 2018, 08:16 ToddAndMargo, <toddandma...@zoho.com <mailto:toddandma...@zoho.com>> wrote:

    Hi All,

    I am confused.

    This line will convert a string into an integer, but
    will print out and extra line with "(Int)" on it:

         $ p6 'my Str $x = "5"; my Int $y = dd +$x; say $y'
         5
         (Int)


    This will convert as well, but no extra line:

         $ p6 'my Int $x; my Str $y = "5"; $x = "$y" + 0; say $x'
         5


    Also, I can quote $x, and it still works:

         $ p6 'my Int $x; my Str $y = "5"; $x = "$y" + 0; say "$x"'
         5


    But this tells me I have an uninitialized value, when all
    I did was add quotes around $y, as in the above line.

         $ p6 'my Str $x = "5"; my Int $y = dd +$x; say "$y";'
         5
         Use of uninitialized value $y of type Int in string context.
         Methods .^name, .perl, .gist, or .say can be used to stringify
         it to something meaningful.


    Why would I want to use "dd"?

    Many thanks,
    -T

On 08/07/2018 12:19 AM, Simon Proctor wrote:

dd is the moarvm specific data dump command. You don't need it.

--
Simon Proctor
Cognoscite aliquid novum cotidie

Thank you!

What is "moarvm"