Hi All, I am confused.
This line will convert a string into an integer, but will print out and extra line with "(Int)" on it: $ p6 'my Str $x = "5"; my Int $y = dd +$x; say $y' 5 (Int) This will convert as well, but no extra line: $ p6 'my Int $x; my Str $y = "5"; $x = "$y" + 0; say $x' 5 Also, I can quote $x, and it still works: $ p6 'my Int $x; my Str $y = "5"; $x = "$y" + 0; say "$x"' 5 But this tells me I have an uninitialized value, when all I did was add quotes around $y, as in the above line. $ p6 'my Str $x = "5"; my Int $y = dd +$x; say "$y";' 5 Use of uninitialized value $y of type Int in string context. Methods .^name, .perl, .gist, or .say can be used to stringify it to something meaningful. Why would I want to use "dd"? Many thanks, -T
