Nathan Wiger writes: > $x =~ /a/; # $x is roughly equivalent to a I've been going at high speed through this thread, but has anyone mentioned: m{$foo}{^baz.*bar$}i s{$foo}{(\w+) \1}{$1}g With the first part of m{} and s{} containing an expression. We lose !~ there, though. Thoughts on how to indicate negation: * use ! as delimiter. Ugh. Special delimiters bad. * use m!{}{}. Ugh. Mixed alnum and punctuation bad. * use ! in front (I like this, as it's back to being normal Perl) ! m{$foo}{^baz.*bar$}i Read as "doesn't match". Nat
- RFC 138 (v1) Eliminate =~ operator. Perl6 RFC Librarian
- Re: RFC 138 (v1) Eliminate =~ operator. Mark-Jason Dominus
- Re: RFC 138 (v1) Eliminate =~ operator. Steve Fink
- Re: RFC 138 (v1) Eliminate =~ operator. Larry Wall
- Re: RFC 138 (v1) Eliminate =~ operato... Steve Fink
- Re: RFC 138 (v1) Eliminate =~ op... Jarkko Hietaniemi
- Re: RFC 138 (v1) Eliminate =~ op... Damian Conway
- Re: RFC 138 (v1) Eliminate =~ operato... Nathan Wiger
- Re: RFC 138 (v1) Eliminate =~ op... Steve Fink
- Re: RFC 138 (v1) Eliminate =... Nathan Wiger
- Re: RFC 138 (v1) Eliminate =~ op... Nathan Torkington
- Re: RFC 138 (v1) Eliminate =... Nathan Wiger
- Re: RFC 138 (v1) Elimina... Nathan Torkington
- Re: RFC 138 (v1) Elimina... Tom Christiansen
- Re: RFC 138 (v1) Elimina... Nathan Torkington
- Re: RFC 138 (v1) Elimina... Nathan Wiger
- Re: RFC 138 (v1) Eliminate =~ operator. Mark-Jason Dominus
- Re: RFC 138 (v1) Eliminate =~ operato... Larry Wall
- Re: RFC 138 (v1) Eliminate =~ op... Piers Cawley
- Re: RFC 138 (v1) Eliminate =~ operator. Tom Christiansen
- working mnemonic for =~ David L. Nicol