Hi, On Fri, Jun 23, 2017 at 12:08:05AM +0800, Antonio Quartulli wrote: > yeah...not sure we need to make some code a bit "obscure" if there is > really no need.
It's only obscure if you forget that 2^0+2^1+2^(n-1) = (2^n)-1... :-)
(Admittedly, it needed quite a bit of thinking at first glance)
gert
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