Brilliant! :) On Fri, Oct 31, 2008 at 1:11 PM, Fred Phillips <[EMAIL PROTECTED]> wrote: > On Fri Oct 31 12:48:52 2008, Paul Robinson wrote: >> >> So the deadline has passed. Has anybody got any code they wish to share? > > Here's my mathsy solution, takes 0.224 seconds to calculate the > 100,000th number in the sequence. It doesn't need to calculate the > previous numbers in the sequence to get the next or to test if a > number is in it. > > > -- > Fred O. Phillips > http://fophillips.org > BBC7 7572 755F 83E0 3209 504A E4F7 874F 1545 9D41 >
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