On Wed, 14 Aug 2024 11:12:06 GMT, Daniel Fuchs <dfu...@openjdk.org> wrote:
>>> I wonder in the case of timeout being equal to 0 what the best way to
>>> handle it is though?
>>
>> The `HttpRequest.Builder.timeout()` doesn't allow for `0` (or negative)
>> value to be specified for the timeout duration. So if the request timeout is
>> indeed specified, then we can be sure that the nanos representation of it
>> here will be greater than 0. We could just add an `assert` for that, after
>> converting it to nanos (when the request timeout is present). Something like
>> this untested code:
>>
>>
>> long timeoutNanos = TimeUnit.SECONDS.toNanos(5);
>> if(request.timeout().isPresent() {
>> final long rtNanos = request.timeout().get().getNano();
>> assert rtNanos > 0 : "unexpected request timeout: " + rtNanos;
>> timeoutNanos = Math.min(timeoutNanos, rt);
>> });
>
> I would just let 0 be 0: no need to split 1ms in 500_000 nanos :-)
That sounds fine to me.
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PR Review Comment: https://git.openjdk.org/jdk/pull/20525#discussion_r1716745294
