Re: C++ question

[Angus Leeming]

On Thursday 25 April 2002 12:48 pm, Lars Gullik Bjønnes wrote:
> Angus Leeming <[EMAIL PROTECTED]> writes:
> >> class Foo {
> >>       class Functor {};
> >>
> >>       void do_stuff() {
> >>            find_if(..., Functor());
> >>       }
> >> };
> |
> | I'm hazy about why not. Because it can go out of scope? See, hazy! Could
> | you lift my fog?
>
> I am not really sure, but just try it and watch your compiler...

? Works for me:

#include <iostream>
#include <string>
#include <algorithm>

using std::string;

class Foo {
public:
        class Functor {
        public:
                Functor(char cin) : c(cin) {}
                bool operator()(char comp) { return c == comp; }
        private:
                char c;
        };

        void do_stuff() {
                string const me("Angus");
                char const c = 'n';
                string::const_iterator begin = me.begin();
                string::const_iterator end   = me.end();
                string::const_iterator it =
                        std::find_if(begin, end, Functor(c));
                if (it == end) {
                        std::cout << c << " not found" << std::endl;
                } else {
                        std::cout << c << " found at pos "
                                  << it - begin << std::endl;
                }
        }
};

int main() {
        Foo foo;
        foo.do_stuff();
        return 0;
}

aleem@pneumon:aleem-> ./trial
n found at pos 1