On Thu, Oct 26, 2006 at 07:00:29PM -0000, [EMAIL PROTECTED] wrote: > changes that only differ in their change time with abs(ct1 - ct2) < 300 sec, > they will be merged (and the later change time is preserved). > Technically, the check for equality (or similarity) is made in > operator==(...). The merging of similar changes happens in method merge().
Using operator==() in that case is misleading as we suddenly have situations with a == b, b == c, and a != c. For fuzzy comparison, a named function should be used. Andre'
