Can anyone explain why the comment preceding mpic_assign_isu() on line 145 says
that the I2C registers are at 0x11020 yet the code on line 146 shows 0x11000?
The MPC8245 user manual shows the external interrupt 0 registers at 0x10200
(paddr=40000) and the I2C registers at 0x11020.
<from storcenter.c> <2.6.25.6>
/*
112 * Interrupt setup and service. Interrrupts on the turbostation come
113 * from the four PCI slots plus onboard 8241 devices: I2C, DUART.
114 */
115static void __init storcenter_init_IRQ(void)
116{
117 struct mpic *mpic;
118 struct device_node *dnp;
119 const void *prop;
120 int size;
121 phys_addr_t paddr;
122
123 dnp = of_find_node_by_type(NULL, "open-pic");
124 if (dnp == NULL)
125 return;
126
127 prop = of_get_property(dnp, "reg", &size);
128 if (prop == NULL) {
129 of_node_put(dnp);
130 return;
131 }
132
133 paddr = (phys_addr_t)of_translate_address(dnp, prop);
134 mpic = mpic_alloc(dnp, paddr, MPIC_PRIMARY | MPIC_WANTS_RESET,
135 16, 32, " OpenPIC ");
136
137 of_node_put(dnp);
138
139 BUG_ON(mpic == NULL);
140
141 /*
142 * 16 Serial Interrupts followed by 16 Internal Interrupts.
143 * I2C is the second internal, so it is at 17, 0x11020.
144 */
145 mpic_assign_isu(mpic, 0, paddr + 0x10200);
146 mpic_assign_isu(mpic, 1, paddr + 0x11000);
147
148 mpic_init(mpic);
149}
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