On 08/04/2014 03:46 PM, Peter Zijlstra wrote:
> On Mon, Aug 04, 2014 at 09:28:45AM +0800, Lai Jiangshan wrote:
>> On 08/01/2014 05:55 AM, Paul E. McKenney wrote:
>>> + rcu_read_lock();
>>> + for_each_process_thread(g, t) {
>>> + if (t != current && ACCESS_ONCE(t->on_rq) &&
>>> + !is_idle_task(t)) {
>>> + get_task_struct(t);
>>> + t->rcu_tasks_nvcsw = ACCESS_ONCE(t->nvcsw);
>>> + ACCESS_ONCE(t->rcu_tasks_holdout) = 1;
>>> + list_add(&t->rcu_tasks_holdout_list,
>>> + &rcu_tasks_holdouts);
>>
>> This loop will collect all the runnable tasks. It is too much tasks.
>> Is it possible to collect only on_cpu tasks or PREEMPT_ACTIVE tasks?
>> It seems hard to achieve it.
>
> Without taking the rq->lock you cannot do that race-free. And we're not
> going to be taking rq->lock here.
It is because we can't fetch task->on_cpu and preempt_count atomically
so that rq->lock is required.
3 bleeding solutions:
1) Allocate one bit in preempt_count to stand for not_on_cpu ( = !task->on_cpu)
2) allocate one bit in nvcsw to stand for on_scheduled (or not_on_scheduled,
see next)
3) introduce task->on_scheduled whose semantics is between on_cpu and on_rq,
on_scheduled = scheduled on cpu or preempted, (not voluntary scheduled out)
But the scheduler doesn't need neither of such things. So these is still no
hope.
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