Set comment and indentation style to be consistent with linux coding style
and the rest of the file, as suggested by Peter Zijlstra
Signed-off-by: Michel Lespinasse <wal...@google.com>
---
lib/rbtree.c | 42 +++++++++++++++++++++++-------------------
1 files changed, 23 insertions(+), 19 deletions(-)
diff --git a/lib/rbtree.c b/lib/rbtree.c
index a38e473..0892670 100644
--- a/lib/rbtree.c
+++ b/lib/rbtree.c
@@ -363,8 +363,7 @@ void rb_erase(struct rb_node *node, struct rb_root *root)
child = node->rb_right;
else if (!node->rb_right)
child = node->rb_left;
- else
- {
+ else {
struct rb_node *old = node, *left;
node = node->rb_right;
@@ -406,17 +405,15 @@ void rb_erase(struct rb_node *node, struct rb_root *root)
if (child)
rb_set_parent(child, parent);
- if (parent)
- {
+ if (parent) {
if (parent->rb_left == node)
parent->rb_left = child;
else
parent->rb_right = child;
- }
- else
+ } else
root->rb_node = child;
- color:
+color:
if (color == RB_BLACK)
__rb_erase_color(child, parent, root);
}
@@ -529,8 +526,10 @@ struct rb_node *rb_next(const struct rb_node *node)
if (RB_EMPTY_NODE(node))
return NULL;
- /* If we have a right-hand child, go down and then left as far
- as we can. */
+ /*
+ * If we have a right-hand child, go down and then left as far
+ * as we can.
+ */
if (node->rb_right) {
node = node->rb_right;
while (node->rb_left)
@@ -538,12 +537,13 @@ struct rb_node *rb_next(const struct rb_node *node)
return (struct rb_node *)node;
}
- /* No right-hand children. Everything down and left is
- smaller than us, so any 'next' node must be in the general
- direction of our parent. Go up the tree; any time the
- ancestor is a right-hand child of its parent, keep going
- up. First time it's a left-hand child of its parent, said
- parent is our 'next' node. */
+ /*
+ * No right-hand children. Everything down and left is smaller than us,
+ * so any 'next' node must be in the general direction of our parent.
+ * Go up the tree; any time the ancestor is a right-hand child of its
+ * parent, keep going up. First time it's a left-hand child of its
+ * parent, said parent is our 'next' node.
+ */
while ((parent = rb_parent(node)) && node == parent->rb_right)
node = parent;
@@ -558,8 +558,10 @@ struct rb_node *rb_prev(const struct rb_node *node)
if (RB_EMPTY_NODE(node))
return NULL;
- /* If we have a left-hand child, go down and then right as far
- as we can. */
+ /*
+ * If we have a left-hand child, go down and then right as far
+ * as we can.
+ */
if (node->rb_left) {
node = node->rb_left;
while (node->rb_right)
@@ -567,8 +569,10 @@ struct rb_node *rb_prev(const struct rb_node *node)
return (struct rb_node *)node;
}
- /* No left-hand children. Go up till we find an ancestor which
- is a right-hand child of its parent */
+ /*
+ * No left-hand children. Go up till we find an ancestor which
+ * is a right-hand child of its parent.
+ */
while ((parent = rb_parent(node)) && node == parent->rb_left)
node = parent;
--
1.7.7.3
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