On 11/1/07, Jeff Garzik <[EMAIL PROTECTED]> wrote:
> +       lo = tf->lbam;
> +       hi = tf->lbam;
> +       ibyte = (hi << 8) | lo;
> +
> +       lo = result_tf->lbam;
> +       hi = result_tf->lbam;

That doesn't look right.
I suspect this was intended:

lo = tf->lbam;
hi = tf->lbah;

Torsten
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