Torsten Kaiser wrote:
On 11/1/07, Jeff Garzik <[EMAIL PROTECTED]> wrote:
+ lo = tf->lbam;
+ hi = tf->lbam;
+ ibyte = (hi << 8) | lo;
+
+ lo = result_tf->lbam;
+ hi = result_tf->lbam;
That doesn't look right.
I suspect this was intended:
lo = tf->lbam;
hi = tf->lbah;
Agreed, will correct.
Thanks,
Jeff
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