Use list_is_singular() instead of open-coding.

Signed-off-by: Geliang Tang <geliangt...@gmail.com>
---
 include/net/sctp/sctp.h | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/include/net/sctp/sctp.h b/include/net/sctp/sctp.h
index f8bcb75bb044..e3bd198b00ae 100644
--- a/include/net/sctp/sctp.h
+++ b/include/net/sctp/sctp.h
@@ -412,7 +412,7 @@ static inline void sctp_skb_set_owner_r(struct sk_buff 
*skb, struct sock *sk)
 /* Tests if the list has one and only one entry. */
 static inline int sctp_list_single_entry(struct list_head *head)
 {
-       return (head->next != head) && (head->next == head->prev);
+       return list_is_singular(head);
 }
 
 static inline bool sctp_chunk_pending(const struct sctp_chunk *chunk)
-- 
2.17.1

Reply via email to