On Mon, Aug 14, 2017 at 11:01:10AM -0400, Waiman Long wrote: > On 08/14/2017 08:01 AM, Will Deacon wrote: > > On Fri, Aug 11, 2017 at 11:06:01AM +0200, Peter Zijlstra wrote: > >> On Thu, Aug 10, 2017 at 02:18:30PM -0400, Waiman Long wrote: > >>> On 08/10/2017 12:22 PM, Waiman Long wrote: > >>>> On 08/10/2017 12:15 PM, Peter Zijlstra wrote: > >>>>> Might as well do an explicit: > >>>>> > >>>>> smp_mb__before_atomic() > >>>>> cmpxchg_relaxed() > >>>>> smp_mb__after_atomic() > >>>>> > >>>>> I suppose and not introduce new primitives. > >>> I think we don't need smp_mb__after_atomic(). The read has to be fully > >>> ordered, but the write part may not need it as the control dependency of > >>> the old value should guard against incorrect action. Right? > >> You'd think that, but IIRC there was something funny about using the SC > >> return flag for control dependencies. Will? > > Yeah, that's right, you can't use the STXR status flag to create control > > dependencies. > > > > Will > > Actually, the code sequence that I plan to use are: > > smp_mb__before_atomic(); > if (cmpxchg_relaxed(&pn->state, vcpu_halted, vcpu_hashed) > != vcpu_halted) > return; > > WRITE_ONCE(l->locked, _Q_SLOW_VAL); > (void)pv_hash(lock, pn); > > I am planning to use the comparison of the returned value (pn->state) > again vcpu_halted as the control dependency. I don't see how the status > flag of STXR is affecting this.
Thanks for the context. I agree that you've got a control dependency in this case, so the WRITE_ONCE will be ordered after the LL part of the cmpxchg. It could still be reordered with respect to the write part, however. Will