On Wed, Apr 06, 2016 at 01:10:57PM +1000, NeilBrown wrote:
> On Wed, Apr 06 2016, Shaohua Li wrote:
>
> > On Tue, Apr 05, 2016 at 03:36:57PM +0200, Lars Ellenberg wrote:
> >> blk_check_plugged() will return a pointer
> >> to an object linked on current->plug->cb_list.
> >>
> >> That list may "at any time" be implicitly cleared by
> >> blk_flush_plug_list()
> >> flush_plug_callbacks()
> >> either as a result of blk_finish_plug(),
> >> or implicitly by schedule() [and maybe other implicit mechanisms?]
> >>
> >> If there is no protection against an implicit unplug
> >> between the call to blk_check_plug() and using its return value,
> >> that implicit unplug may have already happened,
> >> even before the plug is actually initialized or populated,
> >> and we may be using a pointer to already free()d data.
> >
> > This isn't correct. flush plug is never called in preemption, which is
> > designed
> > only called when the task is going to sleep. See sched_submit_work. Am I
> > missing anything?
>
> Ahh yes, thanks.
>
> Only two places call blk_schedule_flush_plug().
> One is io_schedule_timeout() which must be called explicitly.
> There other is, as you say, sched_submit_work(). It starts:
>
> static inline void sched_submit_work(struct task_struct *tsk)
> {
> if (!tsk->state || tsk_is_pi_blocked(tsk))
> return;
>
> so if the task is runnable, then as
> include/linux/sched.h:#define TASK_RUNNING 0
>
> it will never call blk_schedule_flush_plug().
>
> So I don't think you are missing anything, we were.
>
> Lars: have your concerns been relieved or do you still have reason to
> think there is a problem?
So just don't call anything that might_sleep() between
blk_check_plug() and using its return value.
All good.
I thought I must have overlooked something.
Thanks,
Lars
