Am 08.07.2008 um 00:04 schrieb Uri Sala:
Dear James,
Thanks but, again, this is misleading, since the numbers in the
bracket would be 6:5 but there would be 3 notes inside the tuplet. I
don't have 6 attacks but 3. This is the kind of cheating I do in
Sibelius, and that I would like to avoid if possible. Sorry to be so
demanding, but isn't this what lilypond should be about? To output
exactly what you want?
Cheers,
Uri
On MondayJul 7, at MonJul 7|23:44 , James E. Bailey wrote:
Am 07.07.2008 um 22:14 schrieb Uri Sala:
It is a bit more convoluted than that. I will try to make myself
clearer:
I want to write 3 against 5.
a tuplet… is a compression of the duration of a rhythmic value. V
\version "2.11.50"
\relative {
\time 5/16
c16 d e f g
\times 5/6 {a8 f d}
}
So, if I understand correctly, you want 3 eighth notes in the space of
3.5 eighth notes, or as you put it, 3 eighth notes in the space of 5
sixteenth notes. You want to have a bracket containing 3 eighth notes
and then the number defining the tuplet to be, I'm assuming, 3 (eighth
note) : 5 (sixteenth)? Do I understand that correctly? If so:
\version "2.11.50"
\relative {
\time 5/16
c16 d e f g
\override TupletNumber #'text = #(markup #:italic "3" #:fontsize
-3 #:note "8" 1 #:italic ":5" #:fontsize -3 #:note "16" 1)
\times 5/6 {a8 f d}
}
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