On 2012-10-08 00:21, Joseph Rushton Wakeling wrote:
On 10/07/2012 11:52 PM, Reinhold Kainhofer wrote:
There is, however, no check whether the fraction with the durations makes
sense and matches the real tuplet (in most cases, itwill not).
Yes, that's what I mean. I'd like to see something where the fractions
and durations are all derived from the tuplet syntax.
Actually, thinking of it, it would actually be quite simple to calculate
the displayed fraction with durations from the given durations and the
tuplet fraction (except that there is no way to distinguish 3:2 and 4:6).
(m*dur1):(n*dur2) = tuplet fraction
can be easily solved as
m/n = (tuplet fraction)*dur2/dur1
and then reduced to minimal m and n. This could then be displayed as
m{dur1}:n{dur2}
Cheers,
Reinhold
--
------------------------------------------------------------------
Reinhold Kainhofer, reinh...@kainhofer.com, http://www.kainhofer.com
* Financial & Actuarial Math., Vienna Univ. of Technology, Austria
* http://www.fam.tuwien.ac.at/, DVR: 0005886
* Edition Kainhofer, Music Publisher, http://www.edition-kainhofer.com
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