>> Sure, but on the other hand it makes it simpler in that we don't need >> to figure out the aspect ratio of each page (they can be different) >> beforehand. > > Surely we have to do that in order to present it to the user ?
Yes, but no. There is something of a chicken-and-egg problem here. In order to call even the getRendererCount() of XRenderable (which gives the number of pages), you have to pass it set of properties that include "RenderDevice" whose value is an XDevice for a virtual device created with XToolkit's createScreenCompatibleDevice(), which takes bitmap size parameters;) The same property set is passed also to render(). I.e., in order to know what size (well, aspect ratio) a particular page is, you need to render it, and to render it, you need a device, and a bitmap-backed virtual device is created with a specific size. But I might be missing something... BTW, noticed a hilarious thing today: The documentation for XDevice says "If the specified area does not lie entirely in the device, the bits outside are not specified". Oh good. But does it "specify", or even hint, what the bits *inside* are then? Nope. --tml _______________________________________________ LibreOffice mailing list LibreOffice@lists.freedesktop.org http://lists.freedesktop.org/mailman/listinfo/libreoffice
