On 06/01/10 03:42, Agathoklis D. Hatzimanikas wrote:
> Hi Andy,
>
> On Wed, Jan 06, at 12:12 Andrew Benton wrote:
>>
>> ln -s $(awk '{ print $1; print $2; print $3; print $4; print $5 }'
>> /proc/cmdline | sed '/dev/!d;s...@root=/dev/@@') /dev/root
>>
>> That works fine and causes no problems, even on systems which don't use
>> NILFS2, but it isn't pretty. Is there a simpler way to get awk to print
>> all the fields at one go? Or would some other tool (perl?) be more
>> appropriate? That's the main reason I wrote this email, for a bit of
>> scripting advice.
>
> Using your pattern, maybe you can do something like,
>
> ln -sv $(sed 's...@root=/dev/\([^ ]*\)....@\1@' /proc/cmdline) /dev/root
>
That would work if the root= option was the first argument, but grub
puts BOOT_IMAGE= first, giving
andy:~$ sed 's...@root=/dev/\([^ ]*\)....@\1@' /proc/cmdline
BOOT_IMAGE=/boot/bzImage sda2
andy:~$
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