Hi,

 

yes thats true - because DP is for data reduction, while VW is more for cartographic purposes, if i remember correctly.

 

stefan

 

------ Originalnachricht ------
Von: Rahkonen Jukka (MML)
Datum: 27.10.2016 10:55
An: michael.micha...@orange.fr;OpenJump develop and use (jump-pilot-devel@lists.sourceforge.net);
Betreff:Re: [JPP-Devel] Visvalingam-Whyatt simplifier

Hi,

 

I guess which method is better depends on use case. For visualization it may not be critical to cut some narrow branches like at the east coast in this demo  https://bost.ocks.org/mike/simplify/

 

-Jukka-

 

Lähettäjä: Michaud Michael [mailto:m.michael.mich...@orange.fr]
Lähetetty: 27. lokakuuta 2016 16:31
Vastaanottaja: Rahkonen Jukka (MML) <jukka.rahko...@maanmittauslaitos.fi>
Aihe: RE: [JPP-Devel] Visvalingam-Whyatt simplifier

 

Hi Jukka,

 

Yes, the algorithm comes directly from JTS. Here is how MD explains the parameter :

 

"The simplification tolerance is specified as a distance.
This is converted to an area tolerance by squaring it."

 

I tried it quickly on a surface representing a river and noticed that it tends to truncate norrow affluents or to split the original polygon into a disconnected multipolygon. Maybe better for  winding road simplification than for norrow surfaces.

 

Michaël

 

De : "Rahkonen Jukka (MML)"

Date d'envoi : jeudi 27 octobre 2016 à 14h28

A : "OpenJump develop and use (jump-pilot-devel@lists.sourceforge.net)" <jump-pilot-devel@lists.sourceforge.net>

Objet : [JPP-Devel] Visvalingam-Whyatt simplifier

Hi Michaël,

 

I tried http://sourceforge.net/p/jump-pilot/code/5110 with road network data and Visvalingam-Whyatt seems to keep the shape of winding roads better than Douglas-Peucker. I wonder what is the parameter of the function presenting. Is it the maximum delta in area that is accepted when the algorithm is removing vertices?

 

Does the algorithm come directly from JTS?

 

-Jukka Rahkonen-




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