How about `all(f, values)`? On 30 January 2015 at 06:51, Wai Yip Tung <[email protected]> wrote:
> I want to apply function f() over a range of value. f() returns true for > success and false for failure. Since f() is expensive, I want short circuit > computation, i.e. it stops after the first failure. > > In python, I can do this in an elegant way with the all() function and > generator expression. > > if all(f(x) for x in values) > # success > else > # failure > > From what I understand, there is no generator expression in Julia. List > comprehension will evaluate the full list. Even if I try to use for loop, I > can't use the control variable to check if the loop has run to finish or > not. > > i = 0 > for i in 1:length(values) > if !f(values[i]) > break > end > end > # The status is ambiguous if i==length(values) > > My last resort is to add flags to indicate if is success or not. Is there > some more elegant way to do this? > >
