I want to apply function f() over a range of value. f() returns true for
success and false for failure. Since f() is expensive, I want short circuit
computation, i.e. it stops after the first failure.
In python, I can do this in an elegant way with the all() function and
generator expression.
if all(f(x) for x in values)
# success
else
# failure
>From what I understand, there is no generator expression in Julia. List
comprehension will evaluate the full list. Even if I try to use for loop, I
can't use the control variable to check if the loop has run to finish or
not.
i = 0
for i in 1:length(values)
if !f(values[i])
break
end
end
# The status is ambiguous if i==length(values)
My last resort is to add flags to indicate if is success or not. Is there
some more elegant way to do this?