Maybe because you are return reference to the function not a jQuery object:
> return this; Read this post: http://jquery-howto.blogspot.com/2008/12/how-to-create-jquery-plugin-extending.html It explains why you need to return jQuery object. On Sat, Feb 7, 2009 at 1:28 PM, ShurikAg <shuri...@gmail.com> wrote: > > Question related to the same plugin: > > Plugin code: > jQ.fn.table = function(options, titles, data){ > if(jQ(this).length == 0){ > //try to find at least one element > $.log("Matching element "+jQ(this).selector+" was not > found!") > return null; > } > //validate that this element is unique i=on hte page > if(jQ(this).length > 1){ > $.log("The element's selector must be unique on the > page!"); > return null; > } > //check if the elemment is a table > //alert(jQ(this).selector); > if(!jQ(this).is('table')){ > $.log("The element must be valid table element!"); > return null; > } > /** > * Save the selector for further > */ > Selector = jQ(this).selector; > > //extend defaults > Options = jQ.extend({}, Defaults, options); > //init additional data > > //init UI > jQ.fn.table.initUI(); > > return this; > }; > > and I'm running it as: > var $table = $('table'); > $table.table(); > > and I'm always getting: "The element must be valid table element!" > > I've tried to trace what the selector is; and once it is "table" but > the second time (in he same run) is null. Why there are two entries to > this function anyways? I have only one table on the page.
