Thank you very much!!!
I have just answered to all I was interested in this topic!
Thanks.
On Feb 6, 11:13 pm, jQuery Lover <ilovejqu...@gmail.com> wrote:
> 1. you can acces them like this $('tr td', this).each(...); Also see
> here for custom plugins and
> functions:http://jquery-howto.blogspot.com/search/label/plugin
>
> 2. when you use $('table') you'll get a selection of all tables. If
> you do this you would get the same object instance:
>
> var $table = $('table');
> $table.table();
> $table.TableSetTitles({col1:"test", col3: "test3", col5: "notexist"});
>
> 3. if a function takes an argument pass it a $table as parameter ...
> (give us a concrete example, and we could give a proper answer to this
> question...)
>
> ----
> Read jQuery HowTo Resource - http://jquery-howto.blogspot.com
>
> On Sat, Feb 7, 2009 at 10:22 AM, ShurikAg <shuri...@gmail.com> wrote:
>
> > Hi,
>
> > 1.
> > Assume that there is a table on a page:
> > <table>
> > <tr>
> > <td></td>
> > <td></td>
> > </tr>
> > </table>
>
> > and I'm using jQuery to manipulate this table by:
> > $("table").table();
>
> > What is the right way of accessing "td" elements inside the function:
> > (function(jQ) {
> > jQ.fn.table = function(options, titles, data){
> > ...
> > ...
> > }
> > })(jQuery);
>
> > 2.
> > When I'm accessing the same table outside of plugin, like this:
> > $("table").table();
> > $("table").TableSetTitles({col1:"test", col3: "test3", col5:
> > "not
> > exist"});
> > Do I actually accessing the same object instance? If not, what is the
> > right way of doing it?
>
> > 3.
> > If I need to use additional jQuery object (.ajax for instance) by
> > passing the table object to it; what is the right way of doing it?
>
> > Thank you in advance.
