Did you use .load or .ajax? I used .load and it does not work...
On Apr 28, 3:49 pm, Hamish Campbell <[EMAIL PROTECTED]> wrote:
> I've tried it myself - put an alert into the script and you should see
> something happen. jQuery executes script tags on load, but you won't
> see it in generated source regardless.
>
> On Apr 29, 10:33 am, hubbs <[EMAIL PROTECTED]> wrote:
>
> > I am using Firefox and web developer toolkit, then viewing generated
> > source.
>
> > Hamish Campbell wrote:
> > > How are you viewing the generated source?
>
> > > Bare in mind that just because you can't see javascript in the browser
> > > source of a page doesn't mean javascript hasn't been executed.
> > > Likewise, you wouldn't see the html loaded from an ajax call in the
> > > browser source -- as it was injected after the page was initially
> > > served.
>
> > > Put something like alert('loaded!!!') into the js to be loaded and see
> > > if you get a result.
>
> > > Also - you can use an invisiable proxy such as Charles (http://
> > > xk72.com/charles/) to view the raw data moving between the browser and
> > > server during the call.
>
> > > On Apr 29, 7:45�am, hubbs <[EMAIL PROTECTED]> wrote:
> > > > I am loading in some content using .load, and have also used the
> > > > normal ajax function. �It seems that all my javascript that is within
> > > > this content is being stripped out when I view the generated source,
> > > > is this the case?!
>
> > > > If so, can I get around this?- Hide quoted text -
>
> > - Show quoted text -
