How are you viewing the generated source?
Bare in mind that just because you can't see javascript in the browser
source of a page doesn't mean javascript hasn't been executed.
Likewise, you wouldn't see the html loaded from an ajax call in the
browser source -- as it was injected after the page was initially
served.
Put something like alert('loaded!!!') into the js to be loaded and see
if you get a result.
Also - you can use an invisiable proxy such as Charles (http://
xk72.com/charles/) to view the raw data moving between the browser and
server during the call.
On Apr 29, 7:45 am, hubbs <[EMAIL PROTECTED]> wrote:
> I am loading in some content using .load, and have also used the
> normal ajax function. It seems that all my javascript that is within
> this content is being stripped out when I view the generated source,
> is this the case?!
>
> If so, can I get around this?
