Hi!
function ($arg) { use $a, &$b;
Note that neither static not global allow & inside definitions, so from "consistency" point of view it doesn't work.
-- Stanislav Malyshev, Zend Software Architect [EMAIL PROTECTED] http://www.zend.com/ (408)253-8829 MSN: [EMAIL PROTECTED] -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php
