Peter, thanks for the note. I'm on a small screen with fat fingers. I will 
reply fully, tonight or tomorrow. I know the paragraph makes my head spin. 
CharlesSent from a mobile; please excuse the brevity.
-------- Original message --------From: Peter Relson <rel...@us.ibm.com> Date: 
3/4/20  6:33 AM  (GMT-08:00) To: IBM-MAIN@LISTSERV.UA.EDU Subject: Re: Two 
related alias entry address questions <snip>The COPYGROUP statement has the 
same effect as the COPYGRP statement wheneither the input or the output data 
set or both are partitioned format, that is eitherPDS or PDSEs. The function of 
a COPYGROUP statement differs from COPYGRPonly if both of the data sets are 
PDSs. COPYGROUP performs a full group copyoperation when both data sets are 
PDSs. By contrast, a COPYGRP statement withtwo PDSs is the same as a COPY 
statement with those data sets.</snip>Am I mis-reading or is sentence 1 
contradictory with sentence 2?Doesn't "both of the data sets are PDSs" (the 
wording in sentence 2) fall within "either the input or the output data set or 
both are partitioned format, that is either PDS or PDSE" (the wording in 
sentence 1)?No one will get any disagreement from me that having a command 
COPYGRP that is different in any way than COPYGROUP is stupid.<snip>BAR DS 
0D...    END BAR</snip>If the entry point offset for BAR had been non-zero, 
then you did not have that case. If you did have that case, an alias of BAR 
would always have been 0 because BAR is not an external entry point. The binder 
rule is simple: if you have an alias for something that is not known externally 
to the binder, the offset into the module that is used is 0.<snip>No one seems 
surprised or alarmed that IEBCOPY fails an operation but still ends with RC=0 
?</snip>sounds strange, but I don't know the definition of RC=0 for IEBCOPY. 
Maybe the definition of RC=0 is that the syntax was correct and you are 
expected to look at messages for anything beyond that. That would be unexpected 
certainly. For a service that is done asynchronously, that is not an 
unreasonable definition of RC=0 "I successfully did the part of the processing 
that I could do and for which I know the results before returning to you". Of 
course that is not IEBCOPY...Peter Relsonz/OS Core Technology 
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