You have "passed" your first period before your "'.'" in the parse
statement is actually interpreted.
For your data example:
myVar = 'word1 word2 9.12 word3.ext'
The correct parse is:
Parse Value myVar with . . myVal2 '.' .
Each period, or var name, in the parse "eats" one blank delimited word.
For example:
myvar = 'a b c d e f g'
parse var myvar . . 'e' next .
will yield next = 'f', but
parse var myvar . . . . . 'e' next .
will yield next = ''
For your data, I would first parse the words, then parse each var for '.'.
Now, if there is really a special character (or string) that you need to
identify, it is best to parse the before and after data, then parse each
section. This is how you should handle finding options in a parm string
passed to a REXX script:
parse value arg with parms '(' options ')' localopts
parse var parms parm1 parm2 parm3 parm4 parm5 .
parse var options opt1 opt2 opt3 opt4 opt5 opt6 .
parse var localopts lopt1 lopt2 lopt3 lopt4 lopt5 .
For the above to work, the use of ')' *requires* a previous '('.
example: arg = aaa bbb ccc ')' ddd eee
parse value arg with parms '(' options ')' localopts
will yield:
parms = "aaa bbb ccc ) ddd eee"
options = ''
localopts = ''
If this might happen, you would need:
parse value arg with part1 ')' localopts
parse var part1 parms ')' options
parse var parms parm1 parm2 parm3 parm4 parm5 .
parse var options opt1 opt2 opt3 opt4 opt5 opt6 .
parse var localopts lopt1 lopt2 lopt3 lopt4 lopt5 .
Tony Thigpen
Seymour J Metz wrote on 2/24/20 5:50 PM:
Isn't that the same, except for the choice of variable names?
For the type of source string that you're parsing, I'd probably break it into
words with a simple parse and then use a parse var foo bar '.' baz
--
Shmuel (Seymour J.) Metz
http://mason.gmu.edu/~smetz3
________________________________________
From: IBM Mainframe Discussion List [IBM-MAIN@LISTSERV.UA.EDU] on behalf of
Ambros, Thomas [0000010f77c934b1-dmarc-requ...@listserv.ua.edu]
Sent: Monday, February 24, 2020 4:26 PM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: Rexx parse using period as placeholder
You mean like this?
*-* Parse Value myVar with . . . myVal2 '.' .
"word1 word2 9.12 word3.ext"
.> "word1"
.> "word2"
.> "9"
""
.> "12 word3.ext"
But you're correct, variables result in the same behavior:
*-* Parse Value myVar with t1 t2 t3 myVal2 '.' .
"word1 word2 9.12 word3.ext"
"word1"
"word2"
"9"
""
.> "12 word3.ext"
So it is the definition of a blank delimited word that escaped me. I'll look
for a precise definition of one of those in the context of Rexx.
Thomas Ambros
zEnterprise Operating Systems
zEnterprise Systems Management
518-436-6433
-----Original Message-----
From: IBM Mainframe Discussion List <IBM-MAIN@LISTSERV.UA.EDU> On Behalf Of
Seymour J Metz
Sent: Monday, February 24, 2020 16:17
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: Rexx parse using period as placeholder
*** Warning: External message - exercise caution. Think before you click. ***
Why did it surprise you, and what does it have to do with the placeholders?
You'd get the same thing if you used three variable names instead of three
periods. The parse with works because it's using a different template on a
different value: try
parse Value myVar with . . . myVal '.' .
--
Shmuel (Seymour J.) Metz
https://urldefense.proofpoint.com/v2/url?u=http-3A__mason.gmu.edu_-7Esmetz3&d=DwIFAg&c=Y1KkN7JyAPjrAJTUCirS0fy9vQY8xn4_Oh4EEEpbXx4&r=7ds2LAJ99_WyGG6a4BwzaJ7R0vee6JgTc4Txes6yEew&m=RwHovw9Jb8ZzPnV0Fb8JtuHSrWfHboK75HB0QKXv7Dw&s=7RT-emP8kpFQ1NAQn6MxdRyt8N1z8blOyGY0-o_XwNw&e=
________________________________________
From: IBM Mainframe Discussion List [IBM-MAIN@LISTSERV.UA.EDU] on behalf of
Ambros, Thomas [0000010f77c934b1-dmarc-requ...@listserv.ua.edu]
Sent: Monday, February 24, 2020 3:43 PM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Rexx parse using period as placeholder
A trivial item, but this surprised me.
I wanted to parse out the string 'word3' using the period as a place holder.
The input could have a blank delimited string containing an embedded period
before the one I wanted to parse out. The Parse Var as coded didn't work.
Using the Parse Value as coded there does work. I didn't know it would behave
like that. I can't seem to find this documented but I might have overlooked
something.
myVar = 'word1 word2 9.12 word3.ext'
Parse Var myVar . . . myVal '.' .
Parse Value Subword(myVar,4) with myVal2 '.' .
Say 'myVal=' myVal
Say 'myVal2=' myVal2
Exit
Trace R of that code:
3 *-* myVar = 'word1 word2 9.12 word3.ext'
>>> "word1 word2 9.12 word3.ext"
4 *-* Parse Var myVar . . . myVal '.' .
>.> "word1" -
>.> "word2"
>.> "9"
>>> ""
>.> "12 word3.ext"
5 *-* Parse Value Subword(myVar,4) with myVal2 '.' .
>>> "word3.ext"
>>> "word3"
>.> "ext"
6 *-* Say 'myVal=' myVal
>>> "myVal= "
myVal=
7 *-* Say 'myVal2=' myVal2
>>> "myVal2= word3"
myVal2= word3
8 *-* Exit
Thomas Ambros
zEnterprise Operating Systems
zEnterprise Systems Management
518-436-6433
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