Why did it surprise you, and what does it have to do with the placeholders?
You'd get the same thing if you used three variable names instead of three
periods. The parse with works because it's using a different template on a
different value: try
parse Value myVar with . . . myVal '.' .
--
Shmuel (Seymour J.) Metz
http://mason.gmu.edu/~smetz3
________________________________________
From: IBM Mainframe Discussion List [IBM-MAIN@LISTSERV.UA.EDU] on behalf of
Ambros, Thomas [0000010f77c934b1-dmarc-requ...@listserv.ua.edu]
Sent: Monday, February 24, 2020 3:43 PM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Rexx parse using period as placeholder
A trivial item, but this surprised me.
I wanted to parse out the string 'word3' using the period as a place holder.
The input could have a blank delimited string containing an embedded period
before the one I wanted to parse out. The Parse Var as coded didn't work.
Using the Parse Value as coded there does work. I didn't know it would behave
like that. I can't seem to find this documented but I might have overlooked
something.
myVar = 'word1 word2 9.12 word3.ext'
Parse Var myVar . . . myVal '.' .
Parse Value Subword(myVar,4) with myVal2 '.' .
Say 'myVal=' myVal
Say 'myVal2=' myVal2
Exit
Trace R of that code:
3 *-* myVar = 'word1 word2 9.12 word3.ext'
>>> "word1 word2 9.12 word3.ext"
4 *-* Parse Var myVar . . . myVal '.' .
>.> "word1" -
>.> "word2"
>.> "9"
>>> ""
>.> "12 word3.ext"
5 *-* Parse Value Subword(myVar,4) with myVal2 '.' .
>>> "word3.ext"
>>> "word3"
>.> "ext"
6 *-* Say 'myVal=' myVal
>>> "myVal= "
myVal=
7 *-* Say 'myVal2=' myVal2
>>> "myVal2= word3"
myVal2= word3
8 *-* Exit
Thomas Ambros
zEnterprise Operating Systems
zEnterprise Systems Management
518-436-6433
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