On 2/18/2014 2:42 PM, John Gilmore wrote:
continued
uence 0, 1, 2, . . .
by dividing by eight to obtain the bytes offset as quotient and the
bit offset, in the sequence 0, 1, 2, 3, 4, 5, 6, 7 as remainder.
I neither see nor feel between my toes any mud.
There is of course no objection to using a <bit count> derived as
<byte count> x 8, for bullet-proofing and the like, but the
fundamental storage quantity is the byte count.
You seem to be deliberately confounding the issue. There is no efficient
way of testing the validity of a bit number using only bytes. Let me
simplify this for you - when the OP has 62 stores, then the allocation
obviously is for a minimum of 8 bytes, but the value for checking
validity of a bit is 62, not 8, and not 8*8.
Gerhard Postpischil
Bradford, Vermont
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