----- Original Message -----
From: "Seymour J Metz" <sme...@gmu.edu>
Sent: Thursday, September 10, 2020 1:02 AM
You did, in the comment.
No I didn't. You misread it.
________________________________________
From: IBM Mainframe Discussion List <IBM-MAIN@LISTSERV.UA.EDU> on behalf of Robin Vowels
<robi...@dodo.com.au>
Sent: Wednesday, September 9, 2020 11:00 AM
On 2020-09-10 00:33, Seymour J Metz wrote:
Since when is 1.33... an integer?
Who said it was?
A/B (both integers with values 4 and 3 respectively),
yield exactly 1.
________________________________________
From: IBM Mainframe Discussion List <IBM-MAIN@LISTSERV.UA.EDU> on
behalf of Robin Vowels <robi...@dodo.com.au>
Sent: Wednesday, September 9, 2020 10:08 AM
From: "Seymour J Metz" <sme...@gmu.edu>
Sent: Monday, September 07, 2020 4:13 PM
PL/I has never had integers.
It always has had integers.
The arithmetic rules for scaled fixed point are different from those
for integers.
In integer arithmetic, (4/3)*6 is 6 That's not the result you get in
PL/I.
Yes it is, with declarations as shown, as I said before, .
Under IBM rules:
%PROCESS RULES(IBM);
INTEGER_DIVISION:
PROCEDURE OPTIONS (MAIN);
DECLARE (A, B) FIXED DECIMAL (15);
A = 4; B = 3;
PUT (4/3);
PUT (A/B);
PUT ( (A/B) * 6 );
END INTEGER_DIVISION;
/* RESULTS:
1.33333333333333 1 6
*/
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