You did, in the comment.

--
Shmuel (Seymour J.) Metz
http://mason.gmu.edu/~smetz3


________________________________________
From: IBM Mainframe Discussion List <IBM-MAIN@LISTSERV.UA.EDU> on behalf of 
Robin Vowels <robi...@dodo.com.au>
Sent: Wednesday, September 9, 2020 11:00 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: PL/I Integer arithmetic

On 2020-09-10 00:33, Seymour J Metz wrote:
> Since when is 1.33... an integer?

Who said it was?

A/B (both integers with values 4 and 3 respectively),
yield exactly 1.

> ________________________________________
> From: IBM Mainframe Discussion List <IBM-MAIN@LISTSERV.UA.EDU> on
> behalf of Robin Vowels <robi...@dodo.com.au>
> Sent: Wednesday, September 9, 2020 10:08 AM
> Subject: Re: PL/I Integer arithmetic (was: Constant Identifiers)
>
> From: "Seymour J Metz" <sme...@gmu.edu>
> Sent: Monday, September 07, 2020 4:13 PM
>
>
>> PL/I has never had integers.
>
> It always has had integers.
>
>> The arithmetic rules for scaled fixed point are different from those
>> for integers.
>> In integer arithmetic, (4/3)*6 is 6 That's not the result you get in
>> PL/I.
>
> Yes it is, with declarations as shown, as I said before, .
>
> Under IBM rules:
>
> %PROCESS RULES(IBM);
> INTEGER_DIVISION:
>    PROCEDURE OPTIONS (MAIN);
>    DECLARE (A, B) FIXED DECIMAL (15);
>
>    A = 4; B = 3;
>
>    PUT (4/3);
>    PUT (A/B);
>    PUT ( (A/B) * 6 );
>
> END INTEGER_DIVISION;
> /* RESULTS:
>   1.33333333333333                       1                       6
> */

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