Well, Peter, that's certainly consistent with what I see. I'm looking, however, at slide 11 of http://publib.boulder.ibm.com/infocenter/ieduasst/stgv1r0/index.jsp?topic=/c om.ibm.iea.zos/zos/1.9/IntegratingNewAppOnzOS/zOSV1R9_Integrating_newAppl_LE UnicodeServices/player.html . (You may have to unfold that URL.)
It says "R - Roundtrip conversion. Roundtrip conversions between two CCSIDs assure that all characters making the roundtrip arrive as they were originally." How is that going to be accomplished if both 3F and 41 translate to 1A? How will they make the round trip back to what they were? What does technique R mean? I certainly understand that not every character in a given CCSID maps meaningfully to another CCSID. That's why I said "possibly meaningless" in my original question. Charles -----Original Message----- From: IBM Mainframe Discussion List [mailto:[email protected]] On Behalf Of Farley, Peter x23353 Sent: Tuesday, June 12, 2012 8:41 AM To: [email protected] Subject: Re: Anyone a Unicode Services expert? -- roundtrip conversion This is a false assumption: "... every code point in the from CCSID translates to a unique (possibly "meaningless") code point in the to CCSID ...". There is no guarantee that all code points in a given CCSID map to a "unique" code point in any other CCSID. ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
