SU_SEC = SU_HOUR / (ENGINES * 60 * 60) Not quite, I think. You don't get the full 60 seconds for each additional engine. Better:
SU_SEC = SU_HOUR / ((ENGINES * 60 * 60)*FACTOR) Where FACTOR is less than 1.0. -----Original Message----- From: IBM Mainframe Discussion List [mailto:[email protected]] On Behalf Of K Zafirop Sent: Tuesday, May 08, 2012 8:33 AM To: [email protected] Subject: Convert CPU time to MSUs Hello all We would like to convert CPU seconds copnsumed by an address space in 1 hour (CPUSECs) to Service Units (SU). Our machine has 5 engines. Is it true that we have available 18000 CPU seconds? SU = CPUSECs * SU_SEC where SU_SEC = SU_HOUR / (ENGINES * 60 * 60) Where SU_HOUR is the number of our machine available Service Units per Hour and SU_SEC is the equivalent Service units /sec factor. ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN NOTICE: This electronic mail message and any files transmitted with it are intended exclusively for the individual or entity to which it is addressed. The message, together with any attachment, may contain confidential and/or privileged information. Any unauthorized review, use, printing, saving, copying, disclosure or distribution is strictly prohibited. If you have received this message in error, please immediately advise the sender by reply email and delete all copies. ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
