On Mon, Nov 23, 2009 at 10:58 PM, Paul Smith <psm...@gnu.org> wrote:
> On Mon, 2009-11-23 at 22:13 -0600, Peng Yu wrote:
>> $< refers to the first prerequisite. How to refer to the first target?
>
> Not sure what you mean: generally there is only one target.
>
> If you mean in a pattern rule with multiple target patterns, there is no
> way. You can construct it with $*, but since, unlike prerequisites, all
> targets have to be defined right there in the rule it's not as important
> to be able to generically refer to the "first" target.
Suppose I have 'command.sh' that generate files 'a' and 'b'.
If either of 'a' or 'b' is older than 'command.sh', I need to run
'command.sh' again. The following Makefile has two targets, right? I
want to refer to the second target 'b' in this Makefile.
$ cat Makefile
all: a b
a b: command.sh
./command.sh
$ cat command.sh
echo 'a' > a
echo 'b' > b
_______________________________________________
Help-make mailing list
Help-make@gnu.org
http://lists.gnu.org/mailman/listinfo/help-make
