On Thu, 27 Dec 2007 18:19:47 +0200, Wolfgang Jeltsch
<[EMAIL PROTECTED]> wrote:
Am Donnerstag, 27. Dezember 2007 16:34 schrieb Cristian Baboi:
I'll have to trust you, because I cannot test it.
let x=(1:x); y=(1:y) in x==y .
I also cannot test this:
let x=(1:x); y=1:1:y in x==y
In these examples, x and y denote the same value but the result of x ==
y is
_|_ (undefined) in both cases. So (==) is not really equality in
Haskell but
a kind of weak equality: If x doesn’t equal y, x == y is False, but if x
equals y, x == y might be True or undefined.
Thank you.
I can only notice that y always has an even number of 1, which is not the
case for x :-)
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